Answer Key:

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Problem 1 The limiting reagent is H2
The mass of Fe is calculated like so: 

(mass of Fe)(mass of H2) =167.55/8.064=(mass of Fe)/1.45(167.55/8.064)1.45=30.1 

Problem 2 
The limiting reagent is NO
The mass of H2O is calculated like so: 

(mass of H2O) / (mass of NO) = 18.02/30.01 = (mass of H2O) / 8.71 (18.02/30.1)(8.71) = 5.23 

Problem 3
The limiting reagent is NO 
The mass of NO2 is calculated like so: 

(mass of NO2) / (mass of NO) =92.02/60.02 = (mass of NO2) /18.2 (92.02/60.02)(18.2)= 52.4

Problem 4

The limiting reagent is Mg
The mass of Mg3N2 is calculated like so: 

(mass of Mg3N2) / (mass of Mg) = 100.9/72.92999999999999= (mass of Mg3N2) /32.6 (100.9/72.92999999999999) (32.6) = 117

Problem 5 
The limiting reagent is C6H6
The mass of CO2 is calculated like so: 

(mass of CO2) / (mass of C6H6) = 528.12/156.22 = (mass of CO2) / 123 (528.12/156.22)(123) = 135

Problem 6
 The liming reagent is O2
The mass of H2O is calculated like so: 

(mass of H2O) / (mass of O2) = 180.2/352 = (mass of H2O) / 71.4 (180.2/352)(71.4) = 36.6 


Problem 7
The limiting reagent is C6H6S2
The mass of H2O is calculated like so: 

(mass of H2O) / (mass of C6H6S2) = 108.12/284.4 = (mass of H2O) (93.8) = 24.4 

Problem 8 
 The limiting reagent is SiO2
The mass of CO is calculated like so: 

(mass of CO)(mass of SiO2)=56.02/64.06 = (mass of CO) /19.9 (56.02/64.06)(19.9) = 31.0 

Problem 9
The limiting reagent is C2H3Br3
The mass of CO2 is calculated like so: 

(mass of CO2) / (mass of C2H3Br3) = 352.08 / 1067.2 = (mass of CO2) / 4.58 (352.08/1067.2) (4.58) = 4.59


Problem 10 
The limiting reagent is C2H4
The mass of CO2 is calculated like so: 

(mass of CO2) / (mass of C2H4) = 88.02 / 28.05 = (mass CO2) / 124 (88.02 /28.05) (124) = 114